60x^2+68x+8=0

Solution for 60x^2+68x+8=0 equation:

60x^2+68x+8=0

a = 60; b = 68; c = +8;
Δ = b2-4ac
Δ = 682-4·60·8
Δ = 2704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2704}=52$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(68)-52}{2*60}=\frac{-120}{120}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(68)+52}{2*60}=\frac{-16}{120}
=-2/15
$